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Byju's Answer

Standard XII

Chemistry

Conductance of Electrolytic Solution

A conductance...

Question

A conductance cell was filled with 0.01 molar KCl. Its resistance was found to be 150 ohm at $25^{o} C$ . The conductivity was observed to be $0.00177 S c m^{- 1}$ . The cell was when washed and filled with 0.05 molar solution of NaCl whose resistance was found to be 325 ohm. Conductivity of NaCl solution is:

6.189 \times 10^{- 4} S c m^{- 1}

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9.168 \times 10^{- 4} S c m^{- 1}

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8.169 \times 10^{- 4} S c m^{- 1}

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Solution

The correct option is C $8.169 \times 10^{- 4} S c m^{- 1}$
As we know,
cell constant = kR = conductivityresistance
so,
1500.00177 = 325k
$k = 8.169 10^{- 4}$

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A conductance cell was filled with 0.01 molar KCl. Its resistance was found to be 150 ohm at 25oC. The conductivity was observed to be 0.00177Scm−1. The cell was when washed and filled with 0.05 molar solution of NaCl whose resistance was found to be 325 ohm. Conductivity of NaCl solution is:

The correct option is C 8.169×10−4Scm−1As we know,cell constant = kR = conductivity*resistanceso,150*0.00177 = 325*kk=8.169∗10−4

The correct option is C $8.169 \times 10^{- 4} S c m^{- 1}$
As we know,
cell constant = kR = conductivityresistance
so,
1500.00177 = 325k
$k = 8.169 10^{- 4}$