a cricket ball of mass 150 gram moving at 36 M per second strikes a back and returns back along the same lines at 21 m per second what is the change in momentum produced if that reminds in contact with the ball for 1 \ 20 seconds what is the average force exerted in Newton

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Solution

Mass of the ball, m = 150 g = 0.15 kg

Initial speed of the ball, u = -36 m/s( it is taken as negative because one is going and other coming so inorder to accompany direction also)

Final speed of the bal after being hit, v = 21m/s

Impulse = change in momentum = final momentum - initial momentum

= Impulse = 0.15 × (21--36) = 0.1557 = 8.55 Ns

force = impulse/time
=8.55/(1/20)
=8.5520
=171 N

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Q. A cricket ball of mass

150 g

is moving with a velocity of

12 m / s

and is hit by a bat so that the ball is turned back with a velocity of

20 m / s

. The force of blow acts for

0.01 s

on the ball. The average force exerted by the bat on the ball is (in

N

)

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