A cricket ball of mass 500 gm strikes a bat normally with a velocity 30 m/s and rebounds with a velocity 20 m/s in the opposite direction. The impulse of the force exerted by the ball on the bat is:
A
0.5 N.s
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B
1.0 N.s
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C
25 N.s
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D
50 N.s
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Solution
The correct option is B 25 N.s Impulse is given by: I=mΔv=0.5×(20−(−30))=0.5×50 I=25Ns