Question

A cube of side 0.4 m rests on the floor, as shown. Given that the cube has a mass of 200 kg, the pressure exerted by the cube on the floor is ____________. $(g=10Nk{g}^{-1})$

Answer 1

Pressure on floor exerted by cube $=\frac{weightofcube}{Areaofbottomside}$

weight $=mg=\left(200\right)\left(10\right)$

$=2000N$

Area $=a^2=(0.4{)}^2=0.16m^2$

So,

Pressure $=\frac{2000N}{0.16m^2}=12500N/m^2$