Question

A cubical block of wood of density $5g{cm}^{-3}$ with a sides of $10cm$ stands on table. Find the thrust by the block of wood on the table if $g=10m{s}^{-2}$.

Answer 1

Side a = 10cm

So Volume = $V=1000{cm}^3.$

As we know, $Density=\frac{mass}{volume}$

$\rho =\frac{m}{V}$

$\Rightarrow m=5g/c{m}^3\times 1000c{m}^3$

So mass = $5000gm=5kg$

Hence thrust = $5kg\times g=50N.$