A cuboidal swimming pool is 15m long and 12m broad. The sum of the area of the floor and the area of the lid used to cover the pool is equal to the sum of area of the four walls of the pool.
What is the amount of water contained in the swimming pool?

720

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900

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1200

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1800

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1900

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Solution

The correct option is C
1200

$2 (15 + 12) \times h = 4 (15 \times 12)$
$h = \frac{180}{27} m = \frac{20}{3} m$
$∴$ Volume = $15 \times 12 \times \frac{20}{3}$ m $^{3} = 1200 m^{3}$

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A cuboidal swimming pool is 15m long and 12m broad. The sum of the area of the floor and the area of the lid used to cover the pool is equal to the sum of area of the four walls of the pool. What is the amount of water contained in the swimming pool?

The correct option is C 1200 2(15+12)×h=4(15×12) h=18027m=203m ∴Volume = 15×12×203 m3=1200m3

A cuboidal swimming pool is 15m long and 12m broad. The sum of the area of the floor and the area of the lid used to cover the pool is equal to the sum of area of the four walls of the pool.
What is the amount of water contained in the swimming pool?

The correct option is C
1200

$2 (15 + 12) \times h = 4 (15 \times 12)$
$h = \frac{180}{27} m = \frac{20}{3} m$
$∴$ Volume = $15 \times 12 \times \frac{20}{3}$ m $^{3} = 1200 m^{3}$