Question

A current electricity is passed through a copper voltmeter and water voltmeter connected in series. If the copper anode of the copper voltmeter now weighs 16 mg less, hydrogen liberated at the cathode of the water voltmeter measured at STP is about.

• A. 4 ml
• B. 5.6 ml
• C. 6.4 ml
• D. 8 ml

Answer 1

The correct option is B 5.6 ml

$\frac{M_c}{E_{cu}}=\frac{V_{H_2}}{V_{H_2}inc{m}^3}=\frac{16\times {10}^{-3}g}{32}=\frac{V_{H_2}}{11200}$
$\therefore$ Volume of Hydrogen = $5.6c{m}^3$