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Standard XII

Physics

Ideal Gas Equation

A cylinder co...

Question

A cylinder contained 10kg of gas at pressure 10 $^{7}$ N / m $^{2}$ . The quantity of gas taken out of cylinder if final pressure is 2.5 x10 $^{6}$ N/m $^{2}$ is (Assume temperature of gas is constant)

Zero

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7.5 Kg

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2.5 Kg

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5 Kg

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Solution

The correct option is A 7.5 Kg
$\frac{P_{1}}{P_{2}} = \frac{m_{1}}{m_{2}} \frac{10^{7}}{2.5 \times 10^{6}} = \frac{10}{m_{2}} m_{2} = 2.5 k g ∴ Q u a n t i t y o f g a s r e m o v e d = 7.5 k g$

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Similar questions

Q. A cylinder contained 10 kg of gas at pressure

10^{7} N / m^{2} .

The quantity of gas taken out of cylinder if final pressure is

2.5 \times 10^{6} M / m

is (assume the temperature of gas is constant)

Q. A cylinder contains

10 k g

of gas at pressure of

10^{7} N / m^{2}

. When final pressure is reduce to

2.5 \times 10^{6} N / m^{2}

then quantity of gas taken out of the cylinder will be (temperature of gas is constant).

Q. A cylinder contains

10

kg of gas at a pressure of

10^{7}

m^{- 2}

. The quantity of gas taken out of the cylinder, if final pressure is

2.5 \times 10^{6}

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is?

Q. A compressed cylinder of gas contains

1.50 \times 10^{3} g

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gas at a pressure of

2.0 \times 10^{7} P a

and a temperature of

{17.1}^{\circ} C

. What volume of gas has been released into the atmosphere if the final pressure in the cylinder is

1.80 \times 10^{5} P a

? Assume ideal behaviour and that the gas temperature is unchanged.

A gas occupies a volume of 2.5 L at $9 \times 10^{5} N m^{- 2}$ . Calculate the additional pressure required to decrease the volume of the gas to 1.51. Assume temperature is constant.

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A cylinder contained 10kg of gas at pressure 107 N / m2. The quantity of gas taken out of cylinder if final pressure is 2.5 x106 N/m2 is (Assume temperature of gas is constant)

The correct option is A 7.5 KgP1P2=m1m21072.5×106=10m2m2=2.5kg∴Quantityofgasremoved=7.5kg

A cylinder contained 10kg of gas at pressure 10 $^{7}$ N / m $^{2}$ . The quantity of gas taken out of cylinder if final pressure is 2.5 x10 $^{6}$ N/m $^{2}$ is (Assume temperature of gas is constant)

The correct option is A 7.5 Kg
$\frac{P_{1}}{P_{2}} = \frac{m_{1}}{m_{2}} \frac{10^{7}}{2.5 \times 10^{6}} = \frac{10}{m_{2}} m_{2} = 2.5 k g ∴ Q u a n t i t y o f g a s r e m o v e d = 7.5 k g$