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Question

A cylinder contains 0.9 moles of benzene vapour and 0.1 moles of toluene vapour at 50 oC . The pure vapour pressure of benzene liquid and the pure vapour pressure of toluene liquid at 50 oC are 600 torr and 200 torr respectively.
What is the mole fraction of liquid benzene in the solution?

A
0.25
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B
0.75
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C
0.50
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D
0.90
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Solution

The correct option is B 0.75
The mole fraction of benzene in vapour phase,
Ybenzene=0.9=Xbenzene×P0benzenePT (1)
The mole fraction of toluene in vapour phase,
Ytoluene=0.1=Xtoluene×P0toluenePT (2)
Eqn(1)÷Eqn (2)
9=Xbenzene×600Xtoluene×200
9=Xbenzene×600(1Xbenzene)×200 (XA+XB=1)
Xbenzene=0.75

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