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Byju's Answer
Standard XII
Physics
Pascal's Law
A cylinder of...
Question
A cylinder of certain mass is held in vertical position. If the height of the cylinder is
10
c
m
and radius of cross-section is
4
c
m
such that the pressure acting on its bottom surface is
21560
N
m
−
2
, then find the mass of the cylinder?
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Solution
We know pressure is
P
=
w
e
i
g
h
t
a
r
e
a
A
=
π
r
2
=
π
×
(
4
×
10
−
2
)
2
m
2
=
16
π
×
10
−
4
m
2
P
=
21560
N
/
m
2
So
P
=
21560
=
m
g
16
×
π
×
10
−
4
,
g
=
10
m
/
s
2
So
m
=
10.8
K
g
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