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Packing Fraction and Efficiency

A cylinder of...

Question

A cylinder of mass $M$ and radius $R$ is resting on two corner edges $A$ and $B$ as shown in figure. The normal reaction at the edges $A$ and $B$ are :

N_{A} = \sqrt{2} N_{B}

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N_{B} = \sqrt{3} N_{A}

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N_{A} = \frac{M g}{2}

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N_{B} = \frac{2 \sqrt{3} M g}{5}

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Solution

The correct option is B $N_{B} = \sqrt{3} N_{A}$
From the equilibrium, it can be written as,

$N_{B} sin 30^{\circ} = N_{A} sin 60^{\circ}$

$\frac{N_{B}}{2} = \frac{\sqrt{3} N_{A}}{2}$

$N_{B} = \sqrt{3} N_{A}$

Thus, the normal reactions at the edges are $N_{B} = \sqrt{3} N_{A}$ .

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A cylinder of mass M and radius R is resting on two corner edges A and B as shown in figure. The normal reaction at the edges A and B are :

The correct option is B NB=√3NAFrom the equilibrium, it can be written as, NBsin30∘=NAsin60∘ NB2=√3NA2 NB=√3NA Thus, the normal reactions at the edges are NB=√3NA.

A cylinder of mass $M$ and radius $R$ is resting on two corner edges $A$ and $B$ as shown in figure. The normal reaction at the edges $A$ and $B$ are :

The correct option is B $N_{B} = \sqrt{3} N_{A}$
From the equilibrium, it can be written as,

$N_{B} sin 30^{\circ} = N_{A} sin 60^{\circ}$

$\frac{N_{B}}{2} = \frac{\sqrt{3} N_{A}}{2}$

$N_{B} = \sqrt{3} N_{A}$

Thus, the normal reactions at the edges are $N_{B} = \sqrt{3} N_{A}$ .