A cylindrical tank full of water is emptied by a pipe at the rate of $225$ litres per minute. How much time will it take to empty half the tank, if the diameter of its base is $3 m$ and its height is $3.5 m$ ? (Use $π = 22 / 7$ )

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Solution

Volume of cylindrical tank= $π r^{2} h = π \times ({1.5}^{2}) \times 3.5 = 24.75 m^{3} = 24750 l i t r e s$
Rate of discharge or outflow = $225 l / m i n$
Time taken to empty the tank= $\frac{24750}{225} = 110 m i n s = 1 h r 50 m i n s$

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A cylindrical tank full of water is emptied by a pipe at the rate of 225 litres per minute. How much time will it take to empty half the tank, if the diameter of its base is 3m and its height is 3.5m? (Use π=22/7)

Volume of cylindrical tank= πr2h=π×(1.52)×3.5=24.75m3=24750litresRate of discharge or outflow =225 l/minTime taken to empty the tank=24750225=110mins=1hr 50mins

A cylindrical tank full of water is emptied by a pipe at the rate of $225$ litres per minute. How much time will it take to empty half the tank, if the diameter of its base is $3 m$ and its height is $3.5 m$ ? (Use $π = 22 / 7$ )

Volume of cylindrical tank= $π r^{2} h = π \times ({1.5}^{2}) \times 3.5 = 24.75 m^{3} = 24750 l i t r e s$
Rate of discharge or outflow = $225 l / m i n$
Time taken to empty the tank= $\frac{24750}{225} = 110 m i n s = 1 h r 50 m i n s$