The correct option is C 7.389 atm
We are given a decimolar solution of K4[Fe(CN)6], molarity = 0.1 M
Degree of dissociation (α)=50100=0.5
Potassium ferrocyanide dissociates to give,
K4[Fe(CN)6]→4K++[Fe(CN)6]4−
Hence n = 5
α=i−1n−1
0.5=i−15−1
i−1=2
∴i=3
∴ van't Hoff factor is 3
π=i×c×R×T
π=3×0.1×0.0821×300
=7.389 atm