a) Derive an integrated rate equation for rate constant of a first order reaction. b) Draw a graph of potential energy V/S reaction co-ordinates showing the effect of catalyst on activation energy (Ea) of a reaction.
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Solution
a) Consider a general first order reaction R → P The differential rate equation for given reaction can be written as Rate=−d[R]dt=K[R]1 Rearrange above equation. d[R][R]=−K×dt Integrating on both sides of the given equation ∫d[R][R]=−k∫dt ln[R]=−Kt+I ..(1) Where I is Integration constant At t=0 the concentration of reactant [R]=[R]0 where [R]0 is initial concentration of reactant Substituting in equation (1) we get ln [R]0=(−K×0)+I ln [R]0=I(2) Substitute I value in equation (1) ln [R]=−Kt+ln[R]0 Kt=ln[R]0−lnR Kt=ln[R]o[R] or K=1tln[R]0[R]. or K=2.303tlog[R]0[R].