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Question

a) Derive an integrated rate equation for rate constant of a first order reaction.
b) Draw a graph of potential energy V/S reaction co-ordinates showing the effect of catalyst on activation energy (Ea) of a reaction.

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Solution

a) Consider a general first order reaction
R P
The differential rate equation for given reaction can be written as
Rate=d[R]dt=K[R]1
Rearrange above equation.
d[R][R]=K×dt
Integrating on both sides of the given equation
d[R][R]=kdt
ln[R]=Kt+I ..(1)
Where I is Integration constant
At t=0 the concentration of reactant [R]=[R]0 where [R]0 is initial concentration of reactant
Substituting in equation (1) we get
ln [R]0=(K×0)+I
ln [R]0=I (2)
Substitute I value in equation (1)
ln [R]=Kt+ln[R]0
Kt=ln[R]0lnR
Kt=ln[R]o[R]
or K=1tln[R]0[R].
or K=2.303tlog[R]0[R].
873294_946594_ans_9a05d062e71d4d40b65b60717a66d94a.png

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