Question

A dice is thrown once. Find the probability of the event $E$ such that outcome is more than 3.

• A. $\frac{1}{3}$
• B. $\frac{1}{4}$
• C. $\frac{1}{6}$
• D. $\frac{1}{2}$

Answer 1

The correct option is D $\frac{1}{2}$

$P\left(E_2\right)=\frac{No.ofpossibleoutcomesgreaterthan3}{No.ofallpossibleoutcomes}=\frac{3}{6}=\frac{1}{2}$