Question

A dice is thrown once. The probability of getting the square of the number appearing on the dice to be a multiple of 9 is

• A. $\frac{1}{3}$
• B. $\frac{2}{3}$
• C. $\frac{1}{2}$
• D. $\frac{1}{6}$

Answer 1

The correct option is A $\frac{1}{3}$

We know, when a dice is thrown once the outcomes are $1,2,3,4,5,6$

The Square of the outcomes are$1,4,9,16,25,36.$

Now , the Square of the number appearing on the Dice to be a multiple of $9$ are $9$ and $36$.

Hence, the probability of getting the square of the number appearing on the Dice to be a multiple of $9=\frac{2}{6}=\frac{1}{3}$

Therefore,

the probability of getting the square of the number appearing on the Dice to be multiple of $9=\frac{1}{3}$