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Question

A die is thrown find the probability of following events:
(i) A prime number will appear
(ii) A number greater than or equal to 3 will appear
(iii) A number less than or equal to one will appear
(iv) A number more than 6 will appear
(v) A number less than 6 will appear

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Solution

The sample space of the given experiment is given by,
S={1,2,3,4,5,6}
(i) Let A be the event of the occurrence of a prime number A={2,3,5}
P(A)=NumberofoutcomesfavourabletoATotalnumberofpossibleoutcomes=n(A)n(S)=36=12
(ii) Let B be the event of the occurrence of a number greater than or equal to 3 B={3,4,5,6}
P(B)=NumberofoutcomesfavourabletoBTotalnumberofpossibleoutcomes=n(B)n(S)=46=23
(iii) Let C be the event of the occurrence of a number less than or equal to one C={1}
P(C)=NumberofoutcomesfavourabletoCTotalnumberofpossibleoutcomes=n(C)n(S)=16
(iv) Let D be the event of the occurrence of a number greater than 6 D=ϕ
P(D)=NumberofoutcomesfavourabletoDTotalnumberofpossibleoutcomes=n(D)n(S)=06=0
(v) Let E be the event of the occurrence of a number less than 6 E={1,2,3,4,5}
P(E)=NumberofoutcomesfavourabletoETotalnumberofpossibleoutcomes=n(E)n(S)=56

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