Question

A die is thrown once. Find the probability of getting:
i) a number divisible by 3
ii) a factor of 6
iii) either 3 or 4
iv) neither 2 nor 4
v) a number from 1 to 6
vi) a number 7
[6 MARKS]

Answer 1

Each subpart: 1 Mark each

Sample space: {1, 2, 3, 4, 5, 6}
i) {3,6} are divisible by 3.
P(a number divisible by 3) $=\frac{2}{6}=\frac{1}{3}$

ii) P(a factor of 6) $=\frac{4}{6}=\frac{2}{3}$ (1,2,3 and 6 are factors of 6)

iii) P(either 3 or 4) $=\frac{2}{6}=\frac{1}{3}$

iv) P(neither 2 nor 4) $=\frac{4}{6}=\frac{2}{3}$

v) P(a number from 1 to 6) = 1 (sure event)

vi) P(a number 7) = 0 (impossible event)