Question

A die thrown 300 times and the outcomes are noted as given below:

$\begin{array}{ccccccc}\text{Outcome}& 1& 2& 3& 4& 5& 6\\ \text{Frequency}& 60& 72& 54& 42& 39& 33\end{array}$

When a die is thrown at random, what is the probability of getting a

(i) 3?

(ii) 6?

(iii) 5?

(iv) 1?

Answer 1

ANSWER:
Total number of throws = 300
In a random throw of a dice, let E 1 , E 2 , E 3 , E 4 , be the events of getting 3, 6, 5 and 1, respectively. Then,
(i)$P\left(getting3\right)=P\left(E1\right)=\frac{Numberoftimes3appears}{Totalnumberoftrials}=\frac{54}{300}=0.18$
(ii) $P\left(getting6\right)=P\left(E2\right)=\frac{Numberoftimes6appears}{Totalnumberoftrials}=\frac{33}{300}=0.11$

(iii) $P\left(getting5\right)=P\left(E3\right)=\frac{Numberoftimes5appears}{Totalnumberoftrials}=\frac{39}{300}=0.13$
(iv) $P\left(getting1\right)=P\left(E4\right)=\frac{Numberoftimes1appears}{Totalnumberoftrials}=\frac{60}{300}=0.20$