Question

a disc of mass m and radius r is rotated about an axis which is tangential to disc. What is the moment of inertia of the disc about the given axis ?

Answer 1

Dear Student,

$$\begin{gathered} MI\hspace{0.17em}ofthediscaroundtheaxispas\sin gthroughcenterandperpendiculartotheplate. \\ I=\frac{m{r}^2}{2} \\ accordingtoperpendicularaxistheorem \\ theMI\hspace{0.17em}alongtheaxispas\sin gthoroughthecenterbutalongtheplaneofthedisc \\ I\text{'}=\frac{I}{2}=\frac{\frac{m{r}^2}{2}}{2}=\frac{m{r}^2}{4} \\ M\hspace{0.17em}alongtheaxis\tan gentialtodiscbyparallelaxistheorem. \\ I\text{'}\text{'}=I\text{'}+m{r}^2=\frac{5m{r}^2}{4} \\ Regards \end{gathered}$$

Regards