Question

A fair coin is tossed three times. What is the probability of getting two heads and one tail in any order?

• A. $\frac{5}{8}$
• B. $\frac{4}{8}$
• C. $\frac{3}{8}$
• D. $\frac{5}{9}$

Answer 1

The correct option is C $\frac{3}{8}$

Sample space, $S=\left\{\text{HHH, HHT, HTH, HTT, TTT, TTH, THT, THH}\right\}$
Favorable outcomes $=\left\{\text{HHT, HTH, THH}\right\}$
So, the probability that two heads and one tail in any order will be the result $=\frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}=\frac{3}{8}$