A farmer moves aalong a square field of side 10 m in 40 seconds. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from its initial position.
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Solution
Total distance covered 10m in 40sec Total time taken= 2min 20sec= 140sec Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.