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Question

A farmer moves along the boundary of a square field of side 10 m in 40 sec. What will be magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

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Solution

Given

Side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m = 40 s
Thus in 1 second, the farmer covers a distance of 1 m.
Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m
Now the total number of rotations the farmer makes to cover a distance of 140 meters =total distanceperimeter
=3.5
At this point, the farmer is at a point which is diagonally opposite from the starting point.
Thus the displacement s=102+102 from Pythagoras theorem.
s=102=14.14m

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