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Question

# A farmer moves along the boundary(starting from A) of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds ?

A
14.14 m
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B
5 m
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C
15.06 m
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D
14.19 m
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Solution

## The correct option is B 14.14 mThe perimeter of square fieldABCD=4×10m=40m.Time for moving around the 10m square field once =40s.Time for journey of farmer =2min and 20s=140s.Number of times the farmer moved around the square field =14040=312times.For going once around the 'square field, the displacement =0For going thrice around the square field, the displacement =0For going 12 around the square field, the distance covered =40×12=20m.It is obvious from the figure, that if the farmer starts from point A, then he will cover 10m along AB and then 10m along BC.Therefore, displacement of farmer from the point A to point C isAC=√AB2+BC2 =√102+102 ≈14.14 m

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