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Question

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?

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Solution


Given, side of the square field,s = 10 m
Therefore, perimeter = 4×s=4×10=40 m
The farmer moves along the boundary in 40 s.
Seconds in 2 m 20 s=2×60 s+20 s=140 s
Since in 40 s, the farmer moves 40 m, in 1 s distance covered by farmer = 4040=1 m
Therefore, in 140 s, distance covered = 140 m.
Number of rounds covered =140 m40 m=3.5 rounds
If the farmer starts from point A, after 3.5 rounds he will be at point C of the field.
Therefore, displacement AC=(AB)2+(BC)2
=(10)2+(10)2
=100+100
=200
=102
=10×1.414=14.14 m

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