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Question

A farmer moves along the boundary of a square field of slide 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

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Solution

Figure ABCD is squire field side of 10m.
Time for one round=40
Total time=2m20sec
(2×60+20=140s)
Number of round completed
If farmer start from A ,it will complete 3 rounds A
At A .In the last 0.5rounds
starting from A .
He will finish at C.

1025092_1084348_ans_a3d4aa6b749b4c9a9b59377a4fba012f.png

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