Question

A father is $30$ years older than his son. In $12$ years, the man will be three times as old as his son. Find their current ages.

Answer 1

Let the present age of the son be '$x$' years.

Then father's age will be $(x+30)$ years

After $12$ years,

Son's age $=x+12$ years

Father's age $=(x+30)+12=x+42$ years

According to question,

After $12$ years,
Father's age $=3\times$ Son's age

$⟹x+42=3(x+12)$

$⟹x+42=3x+36$

$⟹42-36=3x-x$

$⟹6=2x$

$⟹x=\frac{6}{2}$

$⟹x=3$

The present age of son is $3$ years and the present age of the father is $x+30=3+30=33$ years.