Question

A father is $7$ times as old as his son. Two years ago, the father was $13$ times as old as his son. What are their present ages?

Answer 1

Let the present age of the son be x and that to of his father which is 7 times =7x

Then, 2 years ago their ages :

(x-2) of son

(7x-2) of father

Given, $13(x-2)=7x-2$

Then,

$13x-26=7x-2$

$=13x-7x=26-2$

$6x=24$

or x=4 and that of his father = 28 years
$ageofson=x=4years$
$ageoffather=7x=28years$