A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm.How many such tiles are required to cover a floor of area 1080 $m^{2}$ ?

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Solution

Area of floor =1080 $m^{2}$

Base of parallelogram shaped tile (b) =24 cm

and corresponding height (h)=10 cm

$∴ A r e a o f o n e t i l e = b \times h = 24 \times 10 = 240 c m^{2}$

$= \frac{240}{10000} = \frac{24}{1000} m^{2}$

$∴ N u m b e r o f t i l e s r e q u i r e d = \frac{\frac{1080}{24}}{1000}$

$= 1080 \times \frac{1000}{24} = 45000$ tiles.

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A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm.How many such tiles are required to cover a floor of area 1080 m2 ?

Area of floor =1080 m2 Base of parallelogram shaped tile (b) =24 cm and corresponding height (h)=10 cm ∴ Area of one tile =b×h=24×10=240 cm2 =24010000=241000m2 ∴ Number of tiles required=1080241000 =1080×100024=45000 tiles.

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm.How many such tiles are required to cover a floor of area 1080 $m^{2}$ ?