A force of 100 N acts on a body of mass 2 kg for 10 s. The change in momentum of the body is:

200 N-s

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250 N-s

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500 N-s

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1000 N-s

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Solution

The correct option is C 1000 N-s
$F = \frac{m (v - u)}{t}$

$100 = \frac{2 (v - u)}{10}$

$\Rightarrow (v - u) = 500 m s^{- 1}$

Change in momentum $= m (v - u)$

$= 2 \times (500)$

$= 1000 N - s$

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Q. A force of 200 N acts on a body of mass 2 kg for 10 s. Find the change in the momentum of the body.

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A force of 100 N acts on a body of mass 2 kg for 10 s. The change in momentum of the body is:

The correct option is C 1000 N-sF=m(v−u)t100=2(v−u)10⇒(v−u)=500ms−1Change in momentum =m(v−u)=2×(500)=1000 N−s

The correct option is C 1000 N-s
$F = \frac{m (v - u)}{t}$

$100 = \frac{2 (v - u)}{10}$

$\Rightarrow (v - u) = 500 m s^{- 1}$

Change in momentum $= m (v - u)$

$= 2 \times (500)$

$= 1000 N - s$