Question

A force of 16 N is applied on a block of mass 4 kg with $\mu =0.6$ Then the force of friction acting on the block is 4K newton Find the value of K

• A. 4
• B. 3
• C. 6
• D. 2

Answer 1

The correct option is A 4

$F_r=R_{applied}$
When F applied in lesser than limiting friction.

As the frictional force is greater than applied force.

So the $f_s=f_a$

Then $f_s=16N$