A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is

$0.15 \times 10^{- 3} N - s$

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$0.98 \times 10^{- 3} N - s$

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$1.5 \times 10^{- 3} N - s$

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$2.5 \times 10^{- 3} N - s$

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Solution

The correct option is C
$1.5 \times 10^{- 3} N - s$

$I m p u l s e = f o r c e \times t i m e = 50 \times 10^{- 5} \times 3 = 1.5 \times 10^{- 3} N - s$

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A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is

The correct option is C 1.5×10−3N−s Impulse=force×time=50×10−5×3=1.5×10−3N−s

The correct option is C
$1.5 \times 10^{- 3} N - s$

$I m p u l s e = f o r c e \times t i m e = 50 \times 10^{- 5} \times 3 = 1.5 \times 10^{- 3} N - s$