A fruit is dropped from a height of 20 m. Find the velocity with which it would hit the ground. Take g = 10 ms−2
20 m/s
Since, the acceleration is along the direction of motion, a = + 10ms−2, initial velocity u= 0 and height s= 20 m.
Using v2 = u2 + 2as
v2 = 0 + 2 × 10 × 20 = 400
v = √400 = 20 ms−1