Question

A fruitseller buys some oranges at the rate of 4 for rupee and an equal number at 5 for a rupee. He sells the whole lot at 9 for two rupees find his gain or loss percent .

Answer 1

Let fruitseller buys x oranges at the rate of 4 for a rupee & x oranges at the rate of 5 for a rupee.
hence total buying cost = (x/4 + x/5) rupees.
taking LCM, Total buying cost = 9x/20 rupees.
Total number of oranges bought = 2x
Since whole lot of 2x oranges are sold at 9 for 2 rupees.
Hence selling price of 9 oranges = 2 rupees
Hence selling price of 1 orange = 2/9 rupees
Hence selling price of whole lot of 2x oranges = (2/9)×(2x) rupees = 4x/9 rupees.
difference in selling price and buying cost =
(4x/9) - ( 9x/20) = (4/9 - 9/20)x = -x/180 rupees.
Hence fruitseller suffer loss of x/180 rupees.
Loss percentage = { (x/180)÷(9x/20)}×100% = 100/81 % = 1.2345 %
Regards