A garden is $24 m$ long and $14 m$ wide. There is a path $1 m$ wide outside the garden along its sides. If the path is to be constructed with square marble tiles $20 c m \times 20 c m$ , then how many number of tiles will be require to cover the path ?

1800

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200

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2000

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2150

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Solution

The correct option is C $2000$
It is given that the length of the garden is $24$ m and the breadth is $14$ m.

Therefore, area of the garden is $24 \times 14 = 336$ m $^{2}$

Since, there is $1$ m wide path outside the garden.

Thus, area of garden (including path) is:

$(24 + 2) \times (14 + 2) = 26 \times 16 = 26 \times 16 = 416$ m $^{2}$

Now, area of path $=$ Area of garden (including path) $-$ Area of garden $= 416 - 336 = 80$ m $^{2}$

Now, area of marbles $= 20 \times 20 = 400$ cm $^{2}$

Therefore, marbles required $= \frac{A r e a o f p a t h}{A r e a o f m a r b l e s} = \frac{8, 00, 000}{400} = 2000$

Hence, $2000$ tiles will be required to cover the path.

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A garden is 24 m long and 14 m wide. There is a path 1 m wide outside the garden along its sides. If the path is to be constructed with square marble tiles 20 cm×20cm, then how many number of tiles will be require to cover the path ?

A garden is $24 m$ long and $14 m$ wide. There is a path $1 m$ wide outside the garden along its sides. If the path is to be constructed with square marble tiles $20 c m \times 20 c m$ , then how many number of tiles will be require to cover the path ?