Question

A gas initially at $0^{\circ }C$ is heated so that its pressure and volume are both doubled. What will be its final temperature?

• A. ${819}^{\circ }C$
• B. ${919}^{\circ }C$
• C. ${1092}^{\circ }C$
• D. ${1019}^{\circ }C$

Answer 1

The correct option is A

${819}^{\circ }C$

According to Boyle's law and Charles law,

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\Rightarrow \frac{P_1{V}_1}{273}=\frac{\left(2P_1\right)\left(2V_1\right)}{T_2}Since{T}_1=(0+273)K$

$\Rightarrow T_2=4\times 273=1092K$

$\Rightarrow$ Final Temperature $=(1092-273)K={819}^{\circ }C$