A gas is confined in a chamber of constant volume. When the chamber is immersed in a bath of melting ice, the pressure of the gas is 1000 torr. The final temperature, when the pressure in the manometer indicates an absolute pressure of 400 torr is:

109 K

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273 K

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373 K

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0 K

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Solution

The correct option is A $109 K$
Melting point of ice $= 273 K$

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ at constant $V$ ,

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$\frac{1000}{273} = \frac{400}{T_{2}}$ (at constant $V$ )

$T_{2} = 109.2 K$

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A gas is confined in a chamber of constant volume. When the chamber is immersed in a bath of melting ice, the pressure of the gas is 1000 torr. The final temperature, when the pressure in the manometer indicates an absolute pressure of 400 torr is:

The correct option is A 109 KMelting point of ice =273 K P1V1T1=P2V2T2 at constant V, P1T1=P2T2 1000273=400T2 (at constant V) T2=109.2 K

The correct option is A $109 K$
Melting point of ice $= 273 K$

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ at constant $V$ ,

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$\frac{1000}{273} = \frac{400}{T_{2}}$ (at constant $V$ )

$T_{2} = 109.2 K$