You visited us 1 times! Enjoying our articles? Unlock Full Access!

Dalton's Law of Partial Pressures

A gaseous mix...

Question

A gaseous mixture containing $C O$ , $C H_{4}$ and $N_{2}$ gas has total volume of 40 $m L$ . This mixture is exploded with excess of oxygen, on cooling 30 $m L$ of contraction is observed and when this mixture is treated with aqueous $K O H$ a further contraction of 30 $m L$ is observed. Find the composition of the mixture in $m L$ .

C O = 20, C H_{4} = 10, N_{2} = 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O = 15, C H_{4} = 15, N_{2} = 10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C O = 10, C H_{4} = 15, N_{2} = 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O = 20, C H_{4} = 15, N_{2} = 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C O = 15, C H_{4} = 15, N_{2} = 10$
Let volume of $C O, C H_{4}, N_{2}$ be x, y, z $m L$ respectively.
On explosion with excess of $O_{2}$ the following reaction takes place:
$C O x m L (g) + \frac{1}{2} O_{2} (g) \to C O_{2} x m L (g)$
$C H_{4} y m L (g) + 2 O_{2} (g) \to C O_{2} y m L (g) + 2 H_{2} O (g) 2 y m L$
$N_{2}$ remains unreacted.
On cooling $H_{2} O$ gas liquifies hence, volume reduction of 30 $m L$ is observed.
$∴$ 2y = 30 $⟹$ y = 15
Volume of $C H_{4}$ = 15 $m L$
But volume of $C O_{2}$ = (x + y)
As we know $C O_{2}$ is absorbed on $K O H$ and volume reduction of 30 $m L$ is observed.
(x + y) = 30 $⟹$ x = 15 $m L$
Volume of $C O$ = 15 $m L$
$∵$ x + y+ z = 40 $m L$ $⟹$ z = 10 $m L$
Volume of $N_{2}$ = 10 $m L$

Suggest Corrections

Similar questions

Q. A gaseous mixture containing

C O

C H_{4}

and

N_{2}

gas has total volume of 40

m L

. This mixture is exploded with excess of oxygen, on cooling 30

m L

of contraction is observed and when this mixture is treated with aqueous

K O H

a further contraction of 30

m L

is observed. Find the composition of the mixture in

m L

Q. 10 ml mixture of

C O, C H_{4}

and

N_{2}

, exploded with an excess of oxygen, gave a contraction of 6.5 ml. There was a further contraction of 7ml when the residual gas was treated with

K O H

. Volume of

C O, C H_{4}

and

N_{2}

respectively, is :

Q. 10 ml of a mixture of

C H_{4}, C_{2} H_{4}

and

C O_{2}

were exploded with excess of air. After explosion, there was contraction on cooling of 17 ml and after treatment with KOH, there was further reduction of 14 ml. What is the composition of the mixture?

10ml of mixture of CO,CH₄ and N₂ exploded with excess of oxygen gave a contraction of 6.5ml.There was a further contraction of 7 ml when the residual gas was treated with KOH.What is the amount of CH₄ in the original mixture?

Q. A

20.0 c c

mixture of

C O, C H_{4}

and

H e

gases is exploded by an electric discharge at room temperature with excess of oxygen. The volume contraction is found to be

13.0 c c

A further contraction of

14.0 c c

occurs when the residual gas is treated with

K O H

solution. The composition of the gaseous mixture in terms of volume percentage will be:

Join BYJU'S Learning Program

Explore more

Dalton's Law of Partial Pressures

Standard XII Chemistry

Join BYJU'S Learning Program