Question

A gets as many marks less than B as B gets less than C. If the total marks secured together by them is $270$ and C got $90$ marks more than A, find the marks secured by then individually?

• A. $30,60,180$
• B. $45,90,135$
• C. $40,80,150$
• D. $35,70,165$

Answer 1

The correct option is B $45,90,135$

Given $B-A=C-Bor2B=A+C$

$A+B+C=270andC=90+A$

So, we can say $3B=270B=90$

$180=A+C180=A+A+90A=45$

So,$C$ scored $135$.

$A$ gets $45$, $B$ gets $90$ and $C$ gets $135$,