Question

If A got $40\%$ marks more than $B$ in exam, by what $\%$ is $Bs$ marks less than $As$ ?

• A. $28.57\%$
• B. $7.14\%$
• C. $9.09\%$
• D. $40\%$

Answer 1

Answer: (A)

$28.57\%$

Let $B$ got marks $=100$

Then,Marks of $A=140\%\times 100=140$

Required $\%=\frac{140-100}{140}\times 100=28.57\%$ .