Question

In an examination, $A$ got $10$% marks less than $B$, $B$ got $25$% marks more than $C$, $C$ got $20$% marks less than D. If $A$ got $360$ marks out of $500$, the percentage of marks obtained by $D$ was

• A. $70$
• B. $75$
• C. $80$
• D. $85$

Answer 1

The correct option is C $80$

Let D's mark be $x$.
So, C = $0.8x$, B = $1.25\times \left(0.8x\right)=x$, $A=0.9x$
A has got $\frac{360}{500}$.
So, $0.9x=360\times \frac{100}{500}$ or $x=80$.
D has obtained $80$ marks.