A goods train moves steadily on a level track with a velocity 108 kmph. Snow falls vertically on to it, and accumulates at a constant rate of $10 k g s^{- 1}$ . The additional power required in order to maintain the trains speed despite the snow is:

4.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4.5$ kW
Addition of power will be required to change the K.E of snow.
Power $= \frac{(Δ K . E) s n o w}{t}$
$= \frac{1}{2} \frac{d m}{d t} v^{2}$
$= \frac{1}{2} \times 10 \times (30)^{2}$
$= 4.5 k W$

Suggest Corrections

Similar questions

From a water fall, water is falling at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100m then the power delivered to the turbine is approximately equal to

From a waterfall, water is falling down at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100 m, then the power delivered to the turbine is approximately equal to

Q. A skydiver with mass of

60 k g

is moving at a constant speed of

20 m s^{- 1}

. Rate of work done by gravity is _____. Take

g = 10 m s^{- 2}

A rotating machine is maintained at a uniform angular speed of 150 rad s^-1, with a torque of 100 Nm. The power is

Q. A hoist operated by an electric motor has a mass of 500 kg. It raises a load of 300 kg vertically at a steady speed of 0.2 m/s. Frictional resistance can be taken to be constant at 1200 N. What is the power required?

Join BYJU'S Learning Program

A goods train moves steadily on a level track with a velocity 108 kmph. Snow falls vertically on to it, and accumulates at a constant rate of 10kgs−1. The additional power required in order to maintain the trains speed despite the snow is:

The correct option is A 4.5 kWAddition of power will be required to change the K.E of snow.Power =(ΔK.E)snowt =12dmdtv2 =12×10×(30)2 =4.5 kW

A goods train moves steadily on a level track with a velocity 108 kmph. Snow falls vertically on to it, and accumulates at a constant rate of $10 k g s^{- 1}$ . The additional power required in order to maintain the trains speed despite the snow is:

The correct option is A $4.5$ kW
Addition of power will be required to change the K.E of snow.
Power $= \frac{(Δ K . E) s n o w}{t}$
$= \frac{1}{2} \frac{d m}{d t} v^{2}$
$= \frac{1}{2} \times 10 \times (30)^{2}$
$= 4.5 k W$