A has 50 coins of 10 paise denominations. While B has 10 coins of 50 paise denominations. C has 20 coins of 25 paise denominations while D has 25 coins of 20 paise denominations. The average number of paise per person is
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Solution
NumberofcoinsValueofeachcoinsTotalpaiseA501050×10=500paiseB105010×50=500paiseC202520×25=500paiseD252025×20=500paise Average =500+500+500+5004=20004 = 500 paise.