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Question
A hemisphere the diameter of whose base is equal to the side of a cube is placed upon the upper face of the cube if the side of the cube is 14 cm find the total surface area of the solid combination
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Solution
total area=2 π r2 +6a^2
where r=radius of sphere
a=side of cube
=2*π*(7^2)+6*(14^2)
=1483.87cm^2
where r=radius of sphere
a=side of cube
=2*π*(7^2)+6*(14^2)
=1483.87cm^2
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