A house has four tubelights, three fans and a television. Each tubelight draws $40 W$ . The fan draws $80 W$ and the television draws $100 W$ . On an average, all the tubelights are kept on for $5$ hours, all fans for $12$ hours and the television for $6$ hours everyday. Find the cost of electric energy used in $30$ days at the rate of $R s . 3.00$ per KWH

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Solution

Energy consumed by 4 tubelights per day, $E_{t u b e l i g h t} = (4) (40) (5) = 800$ WH
Energy consumed by 3 fans per day, $E_{f a n} = (3) (80) (12) = 2880$ WH
Energy consumed by television per day, $E_{T V} = (100) (6) = 600$ WH
Total energy consumed per day, $E = E_{t u b e l i g h t} + E_{f a n} + E_{T V}$
$∴$ $E = 800 + 2880 + 600 = 4280$ WH $= 4.280$ KWH per day
Total energy consumed in 30 days, $E_{T} = 30 \times 4.280 = 128.4$ KWH
Cost of electric energy $= R s .$ $3.00 \times 128.4 = R s .$ $385.20$

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