Question

A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages.

Answer 1

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Dear Student
Let the present age of B = x yrs
Now, present age of A = 2x yrs
5 YEARS AGO :
age of B = x-5 yrs
age of A = 2x-5 yrs
Now, according to question :2x - 5 = 3(x - 5)
⇒2x - 5 = 3x - 15
⇒2x - 3x = -15 + 5
⇒-x = -10⇒x = 10
So, present age of B = 10 yrs
present age of A = 20 yrs