A juggler throws the balls in air. How high each ball will rise if he throws n balls per second?

\frac{4 n^{2}}{g}

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\frac{g}{2 n^{2}}

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\frac{g}{4 π^{2}}

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\frac{4 g}{n^{2}}

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Solution

The correct option is B $\frac{g}{2 n^{2}}$
Final Velocity = v = 0
Initial Velocity = u
Time = 1/n seconds

0 = u - g1/n
g/n = u

Now applying third equation of motion,

v2 = u2 - 2gH
0 = g/n g / n - 2gH
-(g/n)2 = - 2gH
g2/n2 = 2gH
g/n2 = 2H
H = g/2n2
Answer: g/ 2n2

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A juggler throws the balls in air. How high each ball will rise if he throws n balls per second?

The correct option is B g2n2Final Velocity = v = 0Initial Velocity = u Time = 1/n seconds0 = u - g*1/ng/n = uNow applying third equation of motion,v2 = u2 - 2gH0 = g/n * g / n - 2gH-(g/n)2 = - 2gHg2/n2 = 2gHg/n2 = 2HH = g/2n2Answer: g/ 2n2

The correct option is B $\frac{g}{2 n^{2}}$
Final Velocity = v = 0
Initial Velocity = u
Time = 1/n seconds

0 = u - g1/n
g/n = u

Now applying third equation of motion,

v2 = u2 - 2gH
0 = g/n g / n - 2gH
-(g/n)2 = - 2gH
g2/n2 = 2gH
g/n2 = 2H
H = g/2n2
Answer: g/ 2n2