A liquid of mass m and specific heat c is heated to temperature 2T. Another liquid of mass m/2 specific heat 2c is heated to a temperature T. If these two liquids are nixed, the resulting temperature mixture is

( 2/3) T

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( 8/5) T

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(3/5)T

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(3/ 2)T

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Solution

The correct option is D (3/ 2)T
$θ_{min} = \frac{m_{1} c_{1} θ_{1} + m_{2} c_{2} θ_{2}}{m_{1} c_{1} + m_{2} c_{2}}$
$= \frac{m \times c \times 2 T + \frac{m}{2} (2 c) T}{m . c + \frac{m}{2} (2 c)}$
$= \frac{3}{2} T$
Hence,
option $(D)$ is correct answer.

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A liquid of mass m and specific heat c is heated to temperature 2T. Another liquid of mass m/2 specific heat 2c is heated to a temperature T. If these two liquids are nixed, the resulting temperature mixture is

The correct option is D (3/ 2)Tθmin=m1c1θ1+m2c2θ2m1c1+m2c2=m×c×2T+m2(2c)Tm.c+m2(2c)=32THence,option (D) is correct answer.

The correct option is D (3/ 2)T
$θ_{min} = \frac{m_{1} c_{1} θ_{1} + m_{2} c_{2} θ_{2}}{m_{1} c_{1} + m_{2} c_{2}}$
$= \frac{m \times c \times 2 T + \frac{m}{2} (2 c) T}{m . c + \frac{m}{2} (2 c)}$
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option $(D)$ is correct answer.