A liquid of mass m and specific heat s is at temperature θ. Another liquid of mass 2 m and specific heat s/2 is at 3θ. If these two liquids are mixed, then calculate the resultant temperature of the mixture.
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Solution
Let the resultant temperature be t According to the principle of calorimetry, Heatlost=Heatgained m×S(−θ+t)=2m×S2×(−t+3θ) t−θ=3θ−t 2t=4θ